解:经观察,所要化简数列的第k项Ak可以表示为Ak=[(n+1-k)+(n-k)]*k=(2n+1-2k)*k=(2n+1)k-2k^2,(k=1;
2,……,n)。∴∑Ak=(2n+1)∑k-2∑k^2=(2n+1)n(n+1)/2-2n(n+1)(2n+1)/6=n(n+1)(2n+1)/6
化简求和运算公式求高手给解答
解:经观察,所要化简数列的第k项Ak可以表示为Ak=[(n+1-k)+(n-k)]*k=(2n+1-2k)*k=(2n+1)k-2k^2,(k=1;
2,……,n)。∴∑Ak=(2n+1)∑k-2∑k^2=(2n+1)n(n+1)/2-2n(n+1)(2n+1)/6=n(n+1)(2n+1)/6